Passing different lists of data to view from controller

First, I am getting data in parsedArray below,

JArray parsedArray = JArray.Parse(stringData);

I have a user defined type list named QuestionAnsweList. Now, For each parsedproperty I have initialized parsedproperty.name as my question and parsedproperty.value as my answer. I want to send Note with question answer whenever I find "/" in the question else send only question and answer in a list. Also, I want to send same Note question answer to be sent together so that I can print them together in view.

List QuestionAnswerList = new List();
foreach (JObject parsedObject in parsedArray.Children())
{
foreach (JProperty parsedProperty in parsedObject.Properties())
{
string Question = parsedProperty.Name.ToString();
//string Answer = Convert.ToString(parsedProperty.Value);
if (Question.Contains("/"))
{
string[] Notes = Question.Split('/');
QuestionAnswer aNoteQuestionAnswer = new QuestionAnswer();
aNoteQuestionAnswer.Note = Notes[0].ToString();
aNoteQuestionAnswer.Question = Notes[1];
aNoteQuestionAnswer.Answer = Convert.ToString(parsedProperty.Value);
QuestionAnswerList.Add(aNoteQuestionAnswer);
}
else
{
QuestionAnswer aQuestionAnswer = new QuestionAnswer();
aQuestionAnswer.Question = Question;
aQuestionAnswer.Answer = Convert.ToString(parsedProperty.Value);
QuestionAnswerList.Add(aQuestionAnswer);
}
}
}
return View(QuestionAnswerList);
}

QuestionAnswer Class :

public class QuestionAnswer
{
public string Note { get; set; }
public string Question { get; set; }
public string Answer { get; set; }
}

My View :

@model IEnumerable
class="table table-bordered">
@foreach (var QuestionAnswers in Model)
{
@QuestionAnswers.Serial
@QuestionAnswers.Note
Question : @QuestionAnswers.Question
Answer : @QuestionAnswers.Answer
}

In the table, I want Question and Answers to print in a trow tag. but Whenever a "/" question found in the controller I want to bind all those questions and answers print them here like In a row note then question answer . There can be many questions answers under same name note.

How can I solve this problem? I have given my tried code of controller model and view

see i am giving general solution as it is do

Create Models Like

public class child

{

public string name { get; set; }

}

public class parrent

{

public string parentname { get; set; }

}

public class GroupedModel

{

public child childdata { get; set; }

public parrent parentdata { get; set; }

}

In Controller create object for child and parent calsss

child childobject=new child();

parent parentobject=new parent();

// assign data ;

childobject.name="Kiran";

parentobject.parentname ="Rahul";

// create object for GroupedModel

GroupedModel groupedobject =new GroupedModel();

groupedobject.childdata =childobject;

groupedobject.parentdata=parentobject;

return View(groupedobject);

now you are returning two objects .... like this u need to implement any query ping me

thanks

1 Reply

Know the answer? Post it — somebody with the same question will find it here.

Madan Shekar7y ago
see i am giving general solution as it is do

Create Models Like

public class child

{

public string name { get; set; }

}

public class parrent

{

public string parentname { get; set; }

}

public class GroupedModel

{

public child childdata { get; set; }

public parrent parentdata { get; set; }

}

In Controller create object for child and parent calsss

child childobject=new child();

parent parentobject=new parent();

// assign data ;

childobject.name="Kiran";

parentobject.parentname ="Rahul";

// create object for GroupedModel

GroupedModel groupedobject =new GroupedModel();

groupedobject.childdata =childobject;

groupedobject.parentdata=parentobject;

return View(groupedobject);

now you are returning two objects .... like this u need to implement any query ping me

thanks