Problem in Round Function C#

Question

hello every one,

well i have very big problem in Round Function when i m putting 3 digit number in text box than its not give me round function but if i m putting 2 digit number in text box than its convert into round function i dont know what wrong with that..............

double num = 100.5; num = Math.Round(num);//100

double num1 = 100.51; num = Math.Round(num);//101

but i want 100.5 as 101..........

hope u understand my problem.

thanks in Advance

Nilanka Dharmadasa · Answer

Hi Naim, Math.Round rounds the number based on the normal rounding concept. It means 100.48 >> 100 100.5 >> 100 100.51 >> 101 100.6 >> 101 If you want to get 101 for all , then you can use Ceiling. 100.48 >> 101 100.5 >> 101 100.51 >> 101 100.6 >> 101 double num = 100.5; num = Math.Ceiling(num);//101 If you want to get 101 only for 100.5 and all values greater than that you have to write your own method like below. public double MyRound(double input) { if ((input - Math.Floor(input)) == 0.5) return Math.Ceiling(input); else return Math.Round(input); } private void button1_Click(object sender, EventArgs e) { double num = 100.5; num = MyRound(num);//101 }

srinivas reddy · Answer

hi nahim you can use MidpointRounding mode,and use AwayFromZero mode...so that u can get your desired output. Math .Round(100.5, MidpointRounding .AwayFromZero it gives 101.

Problem in Round Function C#

Answers (2)