there is error

here i want to make program get the perfect number
and there is a syntax error
i want to know

static void Main(string[] args)
        {
            Console.WriteLine("enter ");
            int x = int.Parse(Console.ReadLine());
            bool p = perfect(x);
            if (p == true)
                Console.WriteLine("perfect");
            else
                Console.WriteLine("not perfect");

        }
        static bool perfect(int x)
        {
            int sum = 0;
            for (int i = 0; i <= x; i++)
            {
                sum += i;
                if (sum == x)
                    return true;
                else
                    if (sum > x)
                        return false;
            }
        }
the error

The problem is that the compiler does not know whether or not your code will always return that is why you have to provide an explicit return in all possibility. You may know that any given situation never gonna happens but the compiler does not.

static bool perfect(int x)
        {
            int sum = 0;
            for (int i = 0; i <= x; i++)
            {
                sum += i;
                if (sum == x)
                    return true;
                else // THIS ELSE THE PROBLEM . IF sum < X then the compiler get lost
                    if (sum > x)
                        return false;
            }

try this

static bool perfect(int x)
        {
            int sum = 0;
            for (int i = 0; i <= x; i++)
            {
                sum += i;
                if (sum == x)
                    return true;
                else
                    if (sum > x)
                        return false;
            }

return false; // Althought this line probably wont be reached you have to provide it.

}

1 Reply

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Jorge L Fernandez17y ago
Accepted answer
The problem is that the compiler does not know whether or not your code will always return that is why you have to provide an explicit return in all possibility. You may know that any given situation never gonna happens but the compiler does not.

static bool perfect(int x)
        {
            int sum = 0;
            for (int i = 0; i <= x; i++)
            {
                sum += i;
                if (sum == x)
                    return true;
                else // THIS ELSE THE PROBLEM . IF sum < X then the compiler get lost
                    if (sum > x)
                        return false;
            }

try this

static bool perfect(int x)
        {
            int sum = 0;
            for (int i = 0; i <= x; i++)
            {
                sum += i;
                if (sum == x)
                    return true;
                else
                    if (sum > x)
                        return false;
            }

return false; // Althought this line probably wont be reached you have to provide it.

}