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c# programming doubt

c# programming doubt

Aravind Chitra

12y2kVisual Basic .NET

hello all,

the following code is not working as expected

CODE

Console.WriteLine("enter alphabet");

int c = Console.Read();

Console.WriteLine(c);

Console.WriteLine("enter string");

string j = Console.ReadLine();

Console.WriteLine(j);

Console.ReadKey();

it doesn't allow to enter the string and just exits the program

but if code is reversed,it works fine

Console.WriteLine("enter string");

string j = Console.ReadLine();

Console.WriteLine(j);

Console.WriteLine("enter alphabet");

int c = Console.Read();

Console.WriteLine(c);

Console.ReadKey();

can anyone explain this??

13 Replies

Know the answer? Post it — somebody with the same question will find it here.

Maha12y ago
Problem with the Console.Read() method. It is explained in following website:
http://www.dotnetperls.com/console-read

'Note: When the Read method is first called, it blocks execution waiting for the input to be sent by the terminal window'.

You can alter the program as follows:

using System;

class Program
{
static void Main(string[] args)
{
Console.Write("Enter alphabet ");
char c = char.Parse(Console.ReadLine());
int x = Convert.ToInt32(c);
Console.WriteLine(x);

Console.Write("Enter string ");
string j = Console.ReadLine();
Console.WriteLine(j);

Console.ReadKey();
}
}
Ajay Yadav12y ago
The Console.Read() methods constantly reads the data and buffers won't ends until some method explicitly ends it. Hence, here one more Console.ReadLine() impose and extra ENTER to terminate the existing buffer...

Console.WriteLine("enter alphabet");

int c = Console.Read();
Console.WriteLine(c);
Console.ReadLine();

Console.WriteLine("enter string");
string j = Console.Read().ToString();
Console.WriteLine(j);
Console.ReadLine();
Wim Sturkenboom12y ago
Whatever you type goes in the keyboard buffer; this includes the (being one or two characters).

Console.Read() reads one character from the keyboard buffer; but the buffer contains both the character(s) that you typed and the . So the next character stays (or next characters stay) in the buffer.

Next you're reading input again (using Console.ReadLine()); this reads the buffer up to (and including) the . after that, the keyboard buffer will be empty.

Note that Console.ReadLine() will strip the .

You can test by typing abc after the first prompt. You will get 'a' (97) back for the first read and 'bc' for the second read.

// edit: correct little mistake in first paragraph
Aravind Chitra12y ago
sorry for the unclear question.I am referring to my original question.code 1 gives wrong result but code 2 gives the correct answer..
Vithal Wadje12y ago
i have not changed any order i have just added Console.ReadLine(); because its require while reading the any line from console
Aravind Chitra12y ago
thanks,the code serves the purpose.But any idea why the same codes as mentioned by me give varying results when order is changed...
Vithal Wadje12y ago
this is code

Console.WriteLine("enter alphabet");
int c = Console.Read();
Console.WriteLine(c);
Console.ReadLine();
Console.WriteLine("Enter string");
string j = Console.ReadLine();
Console.WriteLine("Your Entered String is :"+j);
Console.ReadLine();

this is output
Aravind Chitra12y ago
no still not working.the string entered is not displayed
Aravind Chitra12y ago
in the first case , the output window is like

enter alphabet
a
97
enter string

then it exits

in the second case,the output is like

enter string

haha
haha
enter alphabet
a
97
Vithal Wadje12y ago
use this code,its working

Console.WriteLine("enter alphabet");
int c = Console.Read();
Console.WriteLine(c);
Console.WriteLine("enter string");
string j = Console.ReadLine();
Console.ReadLine();
Console.WriteLine(j);
Console.ReadKey();
Console.ReadLine();
Vithal Wadje12y ago
on which line line the screen exit ?
Aravind Chitra12y ago
thank you for the quick reply but,that doesn't solve the problem
Vithal Wadje12y ago
instead of console.Readkey(), Use console.Readline()