Check for an Integer Value-Without Exception

jaguRita

Hello all,
I want to multiply a number by itself,and the number must be Integer.A program, when i get the input number as a string it wont take it as the input n it will show an error "You are not entered Integer,try with some other number".(Without use of exceptions),Is there any possiblity?
i have written one code.But it shows an exception at run time.
int number=int.parse(console.ReadLine());
if (number <= int.MaxValue && number >= int.MinValue)
{
Console.Write("\n Enter the number :");
number *= number;
Console.WriteLine(number);
}
else
{
Console.WriteLine("You are not entered Integer,try with some other number");
}
Whats wrong with my code?How will i write the code only it will accept Integers not an decimal or string.
or Some Clues to do it.I will find out the way.
As am learner i want to know the things.
Thanks.

2 Replies

Know the answer? Post it — somebody with the same question will find it here.

Manuel19y ago
Also you should check

Math.Abs( numer ) <= Math.Sqrt( int.MaxValue )

because you would get an negative number if you would get a larger number than int.MaxValue
Alan19y ago
If you have .NET 2.0, then using the int.TryParse() method will enable you to do this without throwing an exception:

         int number;
         bool isValid = false;

         do
         {
           Console.Write("\n Enter the number : ");
           isValid = int.TryParse(Console.ReadLine(), out number);
           if (isValid) break;
           Console.WriteLine("\n You have not entered an integer, try with some other number");
         }
         while(!isValid);

         number *= number;
         Console.WriteLine("\n The square of your number is {0}",number);

Notice that you never need to check whether an int lies between its minimum and maximum values. As long as it is an 'int', it must do :)