Convert an int to a int[]

Frohikki

Hi
I'm using the same method for user input. So I have the same method for reading an int and to read in values to a int[] - array. I get a error saying can't convert type int to int[]. I can't use any other method I have to use the same method for collecting data for both the int and the array. Is there any way to solve this.
Greatfull for the help.

5 Replies

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Akkiraju Ivaturi14y ago
The problem is here:

int count = numberOfSalaries - 1;//This should be int Count = numberOfSalaries.
int[] salaries = new int[count];

Let say that I enter number of salaries = 2

Then count = 2-1=1

Now your array Salaries length is int[] Salaries = new int[1] i.e. 1

but your loop is
for (int i = 0; i <= count; i++)
{
}
so here there are two iterations for i=0,1
But your array can accomodate only one value as its length is 1

Salaries[0] = will take your value from command prompt
Salaries[1] = This will give you index outside bounds of the array.

Let us know if you have any questions.
Vulpes14y ago
The problem is this line:

int[] salaries = new int[count];

which should be:

int[] salaries = new int[count + 1];
Frohikki14y ago
Thank you for the replies. It seems to work fine except that i get an error: index outside the bounds of the array. How can that be?

class Program
{
static void Main(string[] args)
{
int numberOfSalaries = (int)ReadInt(false, "Hur många löner vill du mata in: ", 0);
Console.WriteLine("");

int[] salaries;
salaries = (int[])ReadInt(true, "Mata in lön: ", numberOfSalaries);


ProcessSalaries(salaries);
}
static object ReadInt(bool isArray, string Prompt, int numberOfSalaries)
{
while (true) //Loopen möjliggör att användaren får fler inmatningsmöjligheter
{
try
{
if (isArray == true)
{
int count = numberOfSalaries - 1;
int[] salaries = new int[count];
for (int i = 0; i <= count; i++)
{
Console.Write(Prompt);
salaries[i] = int.Parse(Console.ReadLine());
}
return salaries;
}
else
{
Console.Write(Prompt);
int value = int.Parse(Console.ReadLine());

if (value <= 1) //Kollar att det är minst två löner som ska matas in
{
Console.BackgroundColor = ConsoleColor.Red;
Console.ForegroundColor = ConsoleColor.White;
Console.WriteLine("\nBeräkningen måste innehålla minst två löner\n");
Console.ResetColor();
}
else
{
return value;
}
}
}
catch //Fångar felinmatningar
{
Console.BackgroundColor = ConsoleColor.Red;
Console.ForegroundColor = ConsoleColor.White;
Console.WriteLine("\nFel inmatning, endast heltal är tillåtna. Var god försök igen.\n");
Console.ResetColor();
}
}
}
Akkiraju Ivaturi14y ago
As specified by Vulpes, IsArray property let you know whether the type you are passing is an integer or int[].

int[] array = { 1, 2, 3, 4 };
int simpleVariable = 45;
Type t1 = array.GetType();
Type t2 = simpleVariable.GetType();

Console.WriteLine("{0} is an array:", t1.IsArray);
Console.WriteLine("{0} is an array:", t2.IsArray);
Vulpes14y ago
Try this:

using System;

class Test
{
static void Main()
{
Console.WriteLine("Inputting a single number ...\n");
int num = (int)GetInput(false);
Console.WriteLine("\nThe number input is {0}\n", num);

Console.WriteLine("Inputting an array of numbers ...\n");
int[] nums = (int[])GetInput(true);
Console.WriteLine("\nThe numbers input are : \n");
foreach(int n in nums) Console.Write("{0} ", n);
Console.WriteLine();
Console.ReadKey();
}

static object GetInput(bool isArray)
{
if (!isArray)
{
Console.Write(" Enter number : ");
int num = int.Parse(Console.ReadLine());
return num;
}
else
{
Console.Write(" Enter how many numbers to be input : ");
int count = int.Parse(Console.ReadLine());
int[] nums = new int[count];
Console.WriteLine();
for(int i = 0; i < count; i++)
{
Console.Write(" Enter number {0} : ", i + 1);
nums[i] = int.Parse(Console.ReadLine());
}
return nums;
}
}
}