How to resolve the error in c program

There is an error like incompatible pointer conversion while running this code

Program code:

---------------------

#include

struct student

{

int roll;

char name[20];

int age;

int m1,m2,m3,m4,m5;

int total;

};

void main()

{

int i,n;

int percentage;

struct student s;

s[i].total=0;

clrscr();

printf("Student Databse\n--------------------\nEnter the No. of records to be Entered:");

scanf("%d",&n);

for(i=0;i>n;i++)

{

printf("Roll No:");

scanf("%d",&s[i].roll);

printf("Name:");

scanf("%s",&s[i].name);

printf("Age:");

scanf("%d",&s[i].age);

printf("Mark 1: ");

scanf("%d",&s[i].m1);

printf("Mark 2: ");

scanf("%d",&s[i].m2);

printf("Mark 3: ");

scanf("%d",&s[i].m3);

printf("Mark 4: ");

scanf("%d",&s[i].m4);

printf("Mark 5: ");

scanf("%d",&s[i].m5);

}

for(i=0;i>n;i++)

{

printf("Entered details:\n----------------\n");

s[i].total=s[i].m1+s[i].m2+s[i].m3+s[i].m4+s[i].m5;

percentage=(s[i].m1+s[i].m2+s[i].m3+s[i].m4+s[i].m5)/5;

printf("Roll No:%d",s[i].roll);

printf("\nName:%s",s[i].name);

printf("\nAge:%d",s[i].age);

printf("\nMark 1:%d",s[i].m1);

printf("\nMark 2:%d",s[i].m2);

printf("\nMark 3: %d",s[i].m3);

printf("\nMark 4:%d",s[i].m4);

printf("\nMark 5:%d",s[i].m5);

printf("\n Total secured:%d \n percentage:%d",s[i].total,percentage);

}

getch();

}

1 Reply

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Ankit Sharma8y ago
Hi ,

This code has errors.

You are using s[i].total=0;

This won't work coz

1. s is not an array
2. you have not set any values to the int variable i

You have to create an array of structure like this

struct student arr[10];

then you have to iterate loop to set values

Now scanf("%s",&s[i].name); is also wrong as format '%s' expects argument of type 'char *', but here it has type 'char (*)[20]'

change it to

scanf("%s",s[i].name);

Please make these changes and let me know if any issues

I have edited the code and you can find the fully edited and working code here

https://ide.geeksforgeeks.org/sYBZrfXFZ9