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how to sum even numbers less than entry number ?

how to sum even numbers less than entry number ?

Abdalla Elawad

Abdalla Elawad

8y808Visual Basic .NET

hi guys

please help me

This is program use c++ i need to sum numbers less than entry numbers i try to print even numbers less than entry but how to sum it ?

#include

using namespace std;

int main() {

/* Initialize i with 1. */

int i;

int n ;

cout << "Enter Number : ";

cin >> n; //take user input

/* If i is less than or equal to 100. */

while( i <= n){

/* If number is divisible by 2, then print.*/

if(i % 2 == 0){

cout <

}

/* Increment i. */

i++;

}

return 0;

}

5 Replies

Know the answer? Post it — somebody with the same question will find it here.

Suraj Kumar8y ago
Accepted answer
#include
using namespace std;
int main()
{
int positiveInteger;
int startingNumber = 1;
cout << "Please input an integer upto 100." << endl;
cin >> positiveInteger;
int result = 0;
for (int i=startingNumber; i <= positiveInteger; i++)
{
if(i%2==0)
result += i;

}
cout << result;
return 0;
}
0
Abdalla Elawad8y ago
Thank You Suraj
0
Suraj Kumar8y ago
#include
using namespace std;
int main()
{ int n;
int sum=0,sum1=0;
cout<<"enter the number of element"<
cin>>n;
for(int i=0;i<=n;i++)
{
if(i%2==0)
{
sum=sum+i;
}
}
cout<<"sum of even number is = "<
for(int i=0;i<=n;i++)
{
if(i%2!=0)
{
sum1=sum1+i;
}
}
cout<<"sum of odd number is = "<
}
0
Abdalla Elawad8y ago
Hi my brother Suraj , without using array .

Just using :

for loop
while
do while

Thanks
0
Suraj Kumar8y ago
Hi,

You can use with some modification below code

int numarr[10];

int sum = 0, even = 0, odd = 0;

for (int i = 0; i < 10; i++)

{

cin >> numarr[i];

if (numarr[i] % 2 == 0)

even = even + numarr[i];

else

odd = odd + numarr[i];

sum = sum + numarr[i];

}

Thanks

Suraj
0