How to use Model

Ramco Ramco

How i can use below code in a view where List of Locations is also required & Individual Location also.

@foreach (var item in Model.Locations)
{

}

@Html.DisplayNameFor(model => model.Location.Id)	@Html.DisplayNameFor(model => model.Location.Description)	@Html.DisplayNameFor(model => model.Location.IsActive)	Action
@Html.DisplayFor(model => item.Id)	@Html.DisplayFor(model => item.Description)	@if(item.IsActive) { } else { }	@if (item.IsActive) { } else { Delete }

Thanks

3 Replies

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Sachin Singh5y ago
controller code
LocationDb dbLocation = new LocationDb();
Location obj= new Location();
obj.Locations= dbLocation.GetAllLocation().ToList();
Ramco Ramco5y ago
Hi Sachin

I am getting this error -

Server Error in '/' Application.

The model item passed into the dictionary is of type 'System.Collections.Generic.List`1[MyApplication.Models.Location]', but this dictionary requires a model item of type 'MyApplication.Models.Location'.

Description: An unhandled exception occurred during the execution of the current web request. Please review the stack trace for more information about the error and where it originated in the code.

********************** Controller

LocationDb dbLocation = new LocationDb();

dbLocation.GetAllLocation().ToList();

****************************** Index

@model MyApplication.Models.Location

Thanks
Sachin Singh5y ago
you already have Locations and Location properties, simply use them, for multiple you are doing right.Now for single
// for single
@model projectName.Location
// for single
@Model.Id
@Model.Description

// for multiple
@foreach(var item in Model.Locations)
{
@item.Id
@item.Description
}
where class structure is
public class Location
{

public Location()
{
this.Locations=New List();
}
public List Locations{get;set;}
public string Id{get;set;}
public string Description{get;set;}
}