I have {'A': value, 'B': value} dictionary. What is the logic of compa

Rajanikant Hawaldar5y ago

Accepted answer

try below

n=input()
dict = ur dict
if(n=='A'):
if(dict[0]>dict[1]):
.....whateva
else
//Otherway

+3

Shivakumar5y ago

In my case only 2 keys are available.

+2

Rajanikant Hawaldar5y ago

Maybe but there could be other ways like u can do it in a loop for if there are more than 2 keys , but its not required here.

+2

Shivakumar5y ago

I guess this is the only way right? but thanks.

+2

Shivakumar5y ago

yes. I'm thinking if input is 'A' then other will be 'B' but I don't want to do this for now. Maybe there's some shorter way. Like it'll automatically compare with the other key if one is selected.

+2

Rajanikant Hawaldar5y ago

Only two keys always?

+2

Shivakumar5y ago

I want solution using python

+2

Sachin Singh5y ago

follow this

var dict = new Dictionaryint> { { "A", 2 }, { "B", 4 } };
var maxKey = dict.Keys.Max(); // "b"
var maxValue = dict.Values.Max(); // 4
var keyOfMaxValue = dict.Aggregate((x, y) => x.Value > y.Value ? x : y).Key; //"b"

+2