Index out of range error

I checked Vulpes code.Its working fine

Why is this code given by Vulpes not printing 1?

public static void Main()
{ int[] number={9,9,3, 1,1,5,5,5,3,3,9,9};
        int n = number.Length;
        Array.Sort(number);
        Console.WriteLine(number[0]);
        for (int i = 1; i < n; i++)
        {
                if (number[i] != number[i - 1])
                {
                        Console.WriteLine(number[i]);
                }
                }
        }

hi Rani,

Santosh and Vulpes both are right
you can also use linq to object for sorting and get distinct value


int[] number = { 9, 9, 3, 1, 1, 5, 5, 5, 3, 3, 9, 9 };
int[] mynumber = number.Distinct().OrderBy(num => num).ToArray();
foreach (int i in mynumber)
{
    Console.WriteLine(i);
}

hope this will help you.

Rani,

Did you change the for statement so that 'i' starts from 1 rather than 0?

Santosh Kumar Sir,

It is sorted list only

The above traditional method wont work, if the items are unsorted. Sorting should be done first to get unique items if you go with traditional method

If you haven't yet learned LINQ and extension methods, you can also do it using 'traditional' code as follows:

Try this.,
.Distinct() extension method will helps you to get unique element.


public static void Main()
  {
  int[] number = { 1, 1, 3, 3, 3, 5, 5, 5, 9, 9, 9, 9 };
 
  foreach (int i in number.Distinct())
  {
  Console.WriteLine(i);
  }
  Console.Read();
  }