Split records based on multiple separator

Hello, Everyone, I Need Help to Prepare Query in PostgreSQL

I required your help to prepare query in PostgreSQL.

Below is my input.

Here you can find that in Field column has a unique value and Values column has values with multiple separators.

Now I want below output.

Here are the steps:

1. First value should be separated with ";" and generate new column with SplitFields
2. From Spitalfields we have to again separate it with ">>" and in that first value should be considered as Folder and Second Value should be considered as Value

Please help to prepare the query.

I have prepared the same query in SQL server but in PostgreSQL, it didn't work for me as I have no more Idea about PostgreSQL

Here is QUERY for SQL Server:

DECLARE @String varchar(1000)
SELECT
@String = 'AV»ABC1; AC»ACTag; BB»BB1Tag; SampleInner»STag1; Not Privileged (RS)»Priv1tag; Winter 2015 Review»Windter1Tag'
SELECT
*,
LEFT(VALUE, CHARINDEX('»', VALUE) - 1) AS firstname,
SUBSTRING(VALUE, CHARINDEX('»', VALUE) + 1, LEN(VALUE) - (CHARINDEX('»', VALUE) - 1)) AS lastname
FROM (SELECT
SUBSTRING(';' + @String + ';', Number + 1,
CHARINDEX(';', ';' + @String + ';', Number + 1) - Number - 1) AS VALUE
FROM master..spt_values
WHERE Type = 'P'
AND Number <= LEN(';' + @String + ';') - 1
AND SUBSTRING(';' + @String + ';', Number, 1) = ';') AS A

1 Reply

Know the answer? Post it — somebody with the same question will find it here.

Nikunj Satasiya7y ago
Thanks, Puneet Kankar For Your Valuable Replay But I got a Solution.
select field,
       splitfields,
       split_part(splitfields, '»', 1) as folder,
       split_part(splitfields, '»', 2) as value
from (
   select t.field, "values", x.splitfields
   from the_table t
      cross join unnest(string_to_array(t."values", ';')) as x(splitfields)
) x;