NP67 Dimensional Array

Thank you for the explanation, Alan.

For some reason that link doesn't work but, from your description, in the same way that a two dimensional array can be used to represent points on a rectangular surface, I imagine that a three-dimensional array is being used to represent points on the surface of a cube i.e. the third dimension represents one of the six sides.

I'd have thought that, strictly speaking, a rectangular array was just a two dimensional array but the C# Specification does in fact use the term rectangular array to represent any non-jagged multidimensional array, so I guess we can consider that as 'official' :)

Hi Guys

http://en.csharp-online.net/All_about_Arrays_in_CSharp%E2%80%94Instantiating_a_One-Dimensional_or_Rectangular_Array

In the above website Figure 14-5 shows the diagram of a cube to explain three-dimensional array. Cube edges representing the dimensions. My problem is, if

Dimension of the array exceeds the number of available edges in the cube how to represent in a cube. In such a situation if it is appropriate to call rectangular array.   

Anyone knows please explain.

Thank you

Thank you for the explanation, Alan.

In general if you have a 3 dimensional array, such as the one below, where x,y and z are positive integers:

int[, ,] empArray = new int[x, y, z];

then the number of elements in the array is  x * y * z.

So, in the case of this array:

int[, ,] empArray = new int[1, 2, 2];

there are 1 * 2 * 2 = 4 elements

You could set these elements 'manually' as follows:

empArray[0, 0, 0] = 20;

empArray[0, 0, 1] = 30;

empArray[0, 1, 0] = 40;

empArray[0, 1, 1] = 50;

If the initial values of each element are a function of x, y and z, then larger arrays would normally be initialized using three nested 'for' loops.