I realized with the coding I have here.. when the count =4, the text file will record twice.. once with the "time" and once with both "time+string".. How can i avoid this?
I expected that when count =4, record "time+string" only..
private void serialPort1_DataReceived(object sender, System.IO.Ports.SerialDataReceivedEventArgs e)
{
string time = DateTime.Now.ToString("dd/MM/yyyy HH:mm:ss.ff");
RxString = serialPort1.ReadLine();
string[] split = RxString.Split('.'); //split RxString at '.'
string dp = split[1]; //dp contains digit behind '.'
Char c = dp[0]; //c = first decimal place
split[1] = c.ToString();
RxString = split[0] + "." + split[1]; //Re-combine Rxstring
this.Invoke(new EventHandler(DisplayText));
string path = @"C:\\Users\acer\Documents\Data3.txt";
string[] number = RxString.Split(' ');
string unit = split[1];
if (x == unit)
{
count++;
string time2 = DateTime.Now.ToString("HH:mm:ss.ff");
string data2 = time2 + "\r\n";
File.AppendAllText(path, data2);
}
else
{
count = 1;
x = unit;
string data1 = RxString + "\r\n";
File.AppendAllText(path, data1);
}
if (count == 4)
{
string data = time + " " + RxString + "\r\n";
File.AppendAllText(path,data);
count = 0; //reset count
}
Jaipal ReddyPosted Jun 24, 2015, 2:17 AM
Loh JyPosted Jun 24, 2015, 2:16 AM
Upendra Pratap ShahiPosted Jun 24, 2015, 2:02 AM