some questions in C Programming need answers for my mid exam, I really need help.

sami sam

How do we find out in C, if a number is even?

I answer with this:
if(number %2==)
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I have only less than 48 hours before my exam start I have to know the answers of these questions due to my teacher foucs on them for my mid semester exam.
wish me luck, :"(

Regards,
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Assuming an int i already exists, write a for loop that prints 10 %'s on one line, one at a time.
I answer with this:
for (i=0;i<10;i++) {
Printf("% ");
}
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The % operator can be applied to two integers, what is the result of 12 % 5?

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#include

int i, j;
char d;

int main() {
d = 'A';
for (i=0; i<5; i++) {
printf("%*c", 5-i, d);
for (j=1; j<=i; j++) {
printf("B");
}
printf(" ");
}
}
Why we got answer like that, I know because we looped it but how it
functionally is working through the program:
I got output like this:
A
AB
ABB
ABBB
ABBBB
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i AM CONFUAED WITH THIS ONE TOO

Write a C program that contains a void function print_a.
The function produces this pattern on the screen:

A
A A
A A
AAAAA
A A
A A
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What does robust mean when applied to software?

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The following code, which was written to produce 10 lines of output each containing the word 2up, contains 5 errors. Mark each one of them with a circle, and describe why it is an error. [10]

void 2up(void);

int i;

int main() {
for (i:=0; i<10; 1++); {
2up();
}
}

void 2up(void) {
printf("2up ");
}
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Write a C program that contains a global integer variable number and a void functionprint_number.

The function prints the value stored in number.
The output is right justified with leading zeros in a field width of 10 followed by a newline.
e.g. if number has the value 134 then the function print_number produces:

0000000134

The main function sets number to 134 and then calls the print_number function.
it does not work:

#include
int number;
void print_number()
{
printf("%010d ",number);
}
void main {)
{
number=134;
print_number();
system("pause");
}
___________________

2 Replies

Know the answer? Post it — somebody with the same question will find it here.

Vulpes14y ago
Accepted answer
Here's what I think the answers are to the remaining questions :

The second one should be :

for (i=0;i<10;i++) {
printf("%%");
}

You need to 'escape' the % by doubling it, bearing in mind it's normally used to specify a format in the printf() statement. So %% prints just one %.

____________________________________________________________________________________________________

The answer to the third one (12 % 5) is 2 because that's the remainder when 12 is divided by 5.
____________________________________________________________________________________________________

The fourth question works like this:

As 'c' is preceded by *, it formats the character, d (which contains 'A'), in a field (5 - i) characters wide. So, when i is 0 then 'A' is preceded by 4 spaces, when i is 1, 'A' is preceded by 3 spaces and so on.

'B' is then written between 1 and 'i' times. So when 'i' is 0, 'B' is written 0 times, when 'i' is 1 it's written once and so on.

A space is then printed before the next combination.

____________________________________________________________________________________________________

As the question doesn't ask you to do any fancy loops, just do it normally:

void print_A(void);

int main() {
printf(" A\n");
printf(" A A\n");
print_A();
printf("AAAAA\n");
print_A();
print_A();
}

void print_A(){
printf("A A\n");
}

____________________________________________________________________________________________________

Software is said to be robust if performs well not just under normal conditions but under abnormal conditions as well.

____________________________________________________________________________________________________

The errors are :

2up - identifiers can't start with a number; change it to twoup say

In the 'for' statement there are 3 errors:

There shouldn't be a colon after 'i'

1++ should be i++

There shouldn't be a semi-colon at the end of the 'for' statement - otherwise 2up will only print once.

In the 2up function, printf("2up "); should be printf("2up\n"); to print on separate lines.

____________________________________________________________________________________________________

Try:

#include
int number;
void print_number()
{
printf("%010d\n",number); /* now prints a new line after the number */
}
void main() /* left parenthesis instead of left curly brace */
{
number=134;
print_number();
system("pause");
}
0
Jeet gupta14y ago
answer about your question How do we find out in C, if a number is even?
Ans: if(number %2==0)
printf("Number is Even")
0