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the string to extract digits and save to integer array in C

the string to extract digits and save to integer array in C

Ken H

Ken H

13y1.8k

Hello Brother,

how to the string to extract digits and save to integer array in C.

It looks as shown below:

int digits[100]; // Assuming allows 100 sets of figures

input:a54df12jlk264jo5erqa504df45

digits[0]=54;

digits[1]=12;

digits[2]=264;

digits[3]=5;

digits[4]=504;

digits[5]=45;

Regards,

Ken

2 Replies

Know the answer? Post it — somebody with the same question will find it here.

Vulpes13y ago
Accepted answer
Try this:

#include
#include

int main(void)
{
int digits[100]; // Assuming allows 100 sets of figures
char input[] = "a54df12jlk264jo5erqa504df45"; // or get from user
char dest[12];
int start = -1;
int i = 0;
int j = 0;
int k;
int len;

while(input[i])
{
if(isdigit(input[i]))
{
if(start == -1)
{
start = i;
}
}
else if (start > -1)
{
len = i - start;
strncpy(dest, &input[start], len);
dest[len] = '\0';
digits[j] = atoi(dest);
j++;
start = -1;
}

i++;
}

if (start > - 1)
{
len = i - start;
strncpy(dest, &input[start], len);
dest[len] = '\0';
digits[j] = atoi(dest);
}
else
{
j--;
}

for(k = 0; k <= j ; k++) printf("digits[%d] = %d\n", k, digits[k]);

return 0;
}
Ken H13y ago
hi Vulpes,
I've included several header files.now it has the normal operation of the.
thank for you :)
#include
#include
#include
#include
int main(void)
{
unsigned long int digits[100]; // Assuming allows 100 sets of figures
char input[] = "a54df12jlk264jo5erqa504df45"; // or get from user
char dest[12];
int start = -1;
int i = 0;
int j = 0;
int k;
int len;
while(input[i])
{
if(isdigit(input[i]))
{
if(start == -1)
{
start = i;
}
}
else if (start > -1)
{
len = i - start;
strncpy(dest, &input[start], len);
dest[len]='\0';
digits[j]=atoi(dest);
j++;
start=-1;
}
i++;
}
if (start>- 1)
{
len = i - start;
strncpy(dest, &input[start], len);
dest[len]='\0';
digits[j]=atoi(dest);
}
else
{
j--;
}
for(k=0;k<=j;k++) printf("digits[%d]=%d\n", k, digits[k]);
return 0;
}

Regards,

Ken