What is the difference between these two?? The first gives you the add

Suri

5y717

What is the difference between these two?? The first gives you the address of the pointer, yes? What is the second?

int *mypointer;
cout << &mypointer << endl;

cout << mypointer << endl;

3 Replies

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Rajanikant Hawaldar5y ago
Accepted answer
Nop. int *mypointer is a pointer to an object of type int.
You can write pointer to a pointer as:
type **mypointer;
Suri5y ago
That makes sense so &mypointer prints the pointer to the pointer.
Rajanikant Hawaldar5y ago
The first one print the address of mypointer. The second print the adress of the object mypointer point to. You should initialize the pointer until you use it (particularly on local scope).